API Automation Using RestSharp [ Deserialization ]

 

How to Deserialize JSON Response to Class with RestSharp?

 The term Deserialization here means the conversion from the String form of JSON to a Class form. This is also called Object Representation of structured data.

• Add Newtonsoft.json to the project via Nuget Package Manager => Manage Nuget packages for Solutions.

• Create a model class of the json response like this

 public class Users
    {

        public string name { get; set; }
        public string job { get; set; }
        public string id { get; set; }
        public DateTime createdAt { get; set; }

    }

• Make appropriate changes in the code like this

 public class DemoGetTest
    {
        private string BaseUrl = "https://reqres.in/";

        [Test]
        public void DeserializingJsonResponse()
        {
            var restClient = new RestClient(BaseUrl);
            var restRequest = new RestRequest("/api/users?page=2", Method.GET);
            restRequest.AddHeader("Accept", "application/json");
            IRestResponse response = restClient.Execute(restRequest);
            var content = response.Content;

            if (response.IsSuccessful)
            {
                Console.WriteLine("Status Code " + response.StatusCode);
                Console.WriteLine("Response Content " + response.Content);

            }

            //De-serialisation of Response Data 


            Root json = JsonConvert.DeserializeObject<Users>(content);
           
            if(json.data[0].first_name== "Michael")
            {
                Console.WriteLine("operation passed ");
            }

             var jsonobject=JObject.Parse(content);
             int pagevalue =(int)jsonobject.GetValue("page");
           

        }


    }